GRE9277 #34

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Joined: Sat Sep 03, 2011 1:41 pm

GRE9277 #34

Postby polaritons » Sun Mar 24, 2013 2:51 pm

This question asks about conducting cavity driven as an electromagnetic resonator.

I have never heard of conducting cavity before, so I was not familiar with that. Well now I know the boundary condition for a conducting cavity. But can someone give a physical explanation of what a conducting cavity is and how do we get the boundary conditions?

Also, what is an electromagnetic resonator?


Posts: 9
Joined: Tue Sep 01, 2015 10:37 am

Re: GRE9277 #34

Postby Chiron » Tue Sep 01, 2015 12:06 pm

I realize that this is an old post, but I will post in the hope it helps someone else who is studying.

In terms of a conducting cavity, you can just think about any cavity where the surrounding walls are composed entirely of a perfect conductor.

The boundary conditions for a perfect conductor are as follows
$\vec{E^{\|}_2} - \vec{E^{\|}_1} = 0$\\[\tex]<br />$\vec{D^{\perp}_2} - \vec{D^{\perp}_1} = \sigma$
$\vec{B^{\perp}_2} - \vec{B^{\perp}_1} = 0$
$\vec{H^{\|}_2} - \vec{H^{\|}_1} = \vec{k} \times \vec{n}$ \hspace{1cm} where $\vec{k}$ is electric current density and $\vec{n}$ is a vector normal to the surface

For more information about electromagnetic resonators you may want to see this page:

Please let me know if anyone has any questions.


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