mrodruck wrote:The solution says that the overall work done is -300kJ. However, I can't figure out why it is negative. Shouldn't the work done by the isothermal process be positive, as W=PiVi*ln(Vi/Vf)? In this case, Vi > Vf which makes the ln function positive, and you know by looking at the graph it does more work than the isobaric process (which should be negative as W=-PdV). Therefore, I'd think it would have to be positive.
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