sravanskarri wrote:I think the nature of wires does not matter when we are looking for final vlaues for this problem( after long time).Charge flows from the positive plate to the negative till they reach a common voltage. During this the current is non-zero causing some potential drop but once the plates arrive at a common potential, there will be no current and hence no voltage drop.

Conservation of energy ( electrical energy) does not hold here as some amount will be lost as heat, light etc.

one posible way:is to use conservation of charge:

-(1 muF) ( 5) + ( 2muF) ( 5) = ( 1muF + 2MuF) V

V = 5/3 = 1.7 V

YES!!! now it makes sense.. great thanks!!!

One must keep in mind these two points before taking any ETS exam..

Rule1: ETS is never wrong.

Rule2: In case of any doubt refer to Rule 1.

by the way just for fun here is another question..

i discharge a charged capacitor across a resistor. as usual charge conservation will be there. but then where will the charges reside after a long time.. the initial energy stored will eventually be lost as heat from the resistor. and we know after a long time q in the capacitor will be 0. surely, microscopically the drift velocity of the electrons will eventually die out.. then what??